So I showed a static, one note implementation of this paradox.
What if it starts with random notes this time?
This is a post that explores just that.
base note
The idea here is to choose a random note to start with.
I can accomplish this with:
l= rrand(20,60)
octaves
Too get the midi numbers of octave we simply add 12. Let me add multiple octaves to make it fun.
m= l+12
n= m+12
o=n+12
p=o+12
Don’t forget to play these notes
Adding tritonnes
Tritones are defined by being the half of an octave. so I add 6 to every note:
q=l+6
r=m+6
s=n+6
t=o+6
Also: Don’t forget to play these notes